For 4 points, that is (1/2)3=1/8(1/2)^3 = 1/8(1/2)3=1/8, the same 12.5% we measured earlier. There is one such event for each of the NNN points, so we have NNN events each with probability 1/2N−11/2^{N-1}1/2N−1.
I haven’t found this heuristic documented anywhere, but I’ve decided to put it here, because I’ve used it and I can bet I’m not the only one. This heuristic is a scaled down version of the “Service per team” pattern from Microservices.
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Мелания Трамп поблагодарила Россию02:10
The UN has repeatedly warned that the country is at risk of sliding back into full-scale civil war.